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conversion of binary to decimal numbers

* to practice this exercise is advisable to start with small numbers and go gradually increased

First write a number, (this may be short, to understand the concept)

1010011, start exercising now :::
The rule says:
"The value of each position is that of a power base 2 , raised to an exponent equal to the position the least digit a "

1 2 * 0 ^ 6 + 2 * ^ 5 + 1 * 2 ^ 4 + 0 * 2 0 ^ 3 + 2 * 1 ^ 2 + 2 * 1 ^ 1 + 2 * ^ 0

( The Numbers in bold are do we convert numbers)
(Los 2 Numbers in italics represent the base number 2, the base will never change)
(EL symbol is "a high exponent ")
(the number on the right side of Symbol is the exponent)
Features:::
The first" 1 "is in the position 7, the number (counting from der . A left .). The rule says " raised to an exponent equal to the position the digit one less , if you're in the position 7 We're going to subtract 1 and the result is the number of exponent.

now only remains to solve:

1 * 2 ^ 6 + 0 * 2 ^ 5 + 1 * 2 ^ 4 + 0 * 2 ^ 3 + 0 * 2 ^ 2 + 1 * 2 ^ 1 + 1 * 2 ^ 0
64 + 0 + 16 + 0 + 0 + 2 + 1


= 83 1010011 = 83


to practice expressing the sig. Number: 110111


101010 010101 111000

1111110

hope allan understood a little But
class they seek to explain them better.

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